tuppence wrote:Yeah, I understand where you are coming from.
In order to get to a correct place to start discussion on this, though, please learn what the definition of atomic mass is. It has NOTHING to do with the 'weight' of an atom or any subatomic particles. If it did, your statements would be correct. As it is, since we do not 'weigh' atoms or subatomic particles, the weight of a desk or an apple or whatever is not the least affected by any change of atomic mass.
If you are up to it, the following might interest you:
http://www.reciprocalsystem.com/isus/ar ... pdate.html
You will find, in this chemical engineering course, that it is the subject of the first lecture:
http://www.cheme.cornell.edu/courses/ch ... labus.html
This article might help, as it references how mass is determined not by gravity in the subatomic particles, but by how they behave in a magnetic field.
http://www.llnl.gov/str/JanFeb03/Soltz.html
I do hope this helps a bit.
I am sorry, but what a bunch of vague links...
Did you take the chemical engineering course? The only thing the text says is this:
1 Aug, 30 Introduction Continuum hypothesis, macroscopic versus microscopic, units & dimensions Ch.1
That does not say anything about how to measure mass, it just says macroscopic versus microscopic. My guess is that it is about the macroscopic vs microscopic way to look at a process. This guess is based on a course I took within my studies Mechanical Engineering at University here.
https://venus.tue.nl/owinfo-cgi/owi_0695.opl?vakcode=4B260&actkomend=AEnglish texts on the site as well. So I think my guess is pretty good.
I find it pretty difficult to find this reference.
I haven't read your first link yet, I will tomorrow when I have more time.
As for this:
As it is, since we do not 'weigh' atoms or subatomic particles, the weight of a desk or an apple or whatever is not the least affected by any change of atomic mass.
I would like to repeat the formula: F=m*a or F=m*g with g the gravitational constant. If m changes and F (weight) stays the same, the gravtiational constant must have changed. Or is it impossible to use the microscopicly measured mass in this formula?